What are the solutions to the equation s^2+3s+5=0 ?

The solutions to the equation s^2+3s+5=0 are s=-3/2+i(sqrt(11))/2 ,s=-3/2-i(sqrt(11))/2

Find the zeros of s^2+3s+5=0

The zeros of s^2+3s+5=0 are s=-3/2+i(sqrt(11))/2 ,s=-3/2-i(sqrt(11))/2

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s^{2} + 3 s + 5 = 0

s = - \frac{3}{2} + i \frac{11}{2}, s = - \frac{3}{2} - i \frac{11}{2}

Solution steps

s^{2} + 3 s + 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 5 : 11 i

s_{1, 2} = \frac{- 3 \pm 11 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 3 + 11 i}{2 \cdot 1}, s_{2} = \frac{- 3 - 11 i}{2 \cdot 1}

s = \frac{- 3 + 11 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{11}{2}

s = \frac{- 3 - 11 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

s = - \frac{3}{2} + i \frac{11}{2}, s = - \frac{3}{2} - i \frac{11}{2}

6 \cdot 0.5

\frac{3}{5} x - 1 = 2

g (f (2))

13 y^{2} + 10 y - 3 = 5 y^{2}

2 x + 3 > 0

What are the solutions to the equation s^2+3s+5=0 ?
The solutions to the equation s^2+3s+5=0 are s=-3/2+i(sqrt(11))/2 ,s=-3/2-i(sqrt(11))/2
Find the zeros of s^2+3s+5=0
The zeros of s^2+3s+5=0 are s=-3/2+i(sqrt(11))/2 ,s=-3/2-i(sqrt(11))/2