What is the answer to (3(4x+1))/7-(6(x-3))/5 =3 ?

The answer to (3(4x+1))/7-(6(x-3))/5 =3 is x=-2

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(3(4x+1))/7-(6(x-3))/5 =3

\frac{3 ( 4 x + 1 )}{7} - \frac{6 ( x - 3 )}{5} = 3

x = - 2

Solution steps

\frac{3 ( 4 x + 1 )}{7} - \frac{6 ( x - 3 )}{5} = 3

Multiply by LCM

15 (4 x + 1) - 42 (x - 3) = 105

Expand

15 (4 x + 1) - 42 (x - 3) : 18 x + 141

18 x + 141 = 105

Move

141

to the right side

18 x = - 36

Divide both sides by

18

x = - 2

- 11 - 4 = - \frac{9}{4} t

9 x + 3 x - 2 \geq 7 - x

4 x^{2} - 1 > 0

x^{2} - 9 x > - 18

(4 + 2 i) (5 - 6 i)

What is the answer to (3(4x+1))/7-(6(x-3))/5 =3 ?
The answer to (3(4x+1))/7-(6(x-3))/5 =3 is x=-2
Solve for x: (3(4x+1))/7-(6(x-3))/5 =3
The solution is x=-2