What are the solutions to the equation 5x^2-6x+2=0 ?

The solutions to the equation 5x^2-6x+2=0 are x= 3/5+i 1/5 ,x= 3/5-i 1/5

Find the zeros of 5x^2-6x+2=0

The zeros of 5x^2-6x+2=0 are x= 3/5+i 1/5 ,x= 3/5-i 1/5

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5 x^{2} - 6 x + 2 = 0

x = \frac{3}{5} + i \frac{1}{5}, x = \frac{3}{5} - i \frac{1}{5}

Solution steps

5 x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

Simplify

(- 6)^{2} - 4 \cdot 5 \cdot 2 : 2 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 5}, x_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 5}

x = \frac{- ( - 6 ) + 2 i}{2 \cdot 5} : \frac{3}{5} + i \frac{1}{5}

x = \frac{- ( - 6 ) - 2 i}{2 \cdot 5} : \frac{3}{5} - i \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{3}{5} + i \frac{1}{5}, x = \frac{3}{5} - i \frac{1}{5}

x^{\frac{3}{2}}

\frac{20 + 5 i}{20 - 5 i}

2 x - 1 = - 6

3 + x > 7

\frac{1}{2} - \frac{3}{4}

What are the solutions to the equation 5x^2-6x+2=0 ?
The solutions to the equation 5x^2-6x+2=0 are x= 3/5+i 1/5 ,x= 3/5-i 1/5
Find the zeros of 5x^2-6x+2=0
The zeros of 5x^2-6x+2=0 are x= 3/5+i 1/5 ,x= 3/5-i 1/5