What are the solutions to the equation (2x-10)(x+6)=0 ?

The solutions to the equation (2x-10)(x+6)=0 are x=5,x=-6

Find the zeros of (2x-10)(x+6)=0

The zeros of (2x-10)(x+6)=0 are x=5,x=-6

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(2 x - 10) (x + 6) = 0

x = 5, x = - 6

Solution steps

(2 x - 10) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 10 = 0 or x + 6 = 0

Solve

2 x - 10 = 0 : x = 5

Solve

x + 6 = 0 : x = - 6

The solutions to the quadratic equation are:

x = 5, x = - 6

- 2 (1 + 3 b) > 1 - 6 b

(\frac{64}{27})^{\frac{2}{3}}

3 (2 x - 3) \geq 2 (x + 5) - 1

\frac{2}{5 5}

x^{2} + 4 x y - 12 y^{2}

What are the solutions to the equation (2x-10)(x+6)=0 ?
The solutions to the equation (2x-10)(x+6)=0 are x=5,x=-6
Find the zeros of (2x-10)(x+6)=0
The zeros of (2x-10)(x+6)=0 are x=5,x=-6