What are the solutions to the equation 5u^2-7u-6=0 ?

The solutions to the equation 5u^2-7u-6=0 are u=2,u=-3/5

Find the zeros of 5u^2-7u-6=0

The zeros of 5u^2-7u-6=0 are u=2,u=-3/5

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5 u^{2} - 7 u - 6 = 0

u = 2, u = - \frac{3}{5}

Solution steps

5 u^{2} - 7 u - 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 6) = 13

u_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 5}

Separate the solutions

u_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 5}, u_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 5}

u = \frac{- ( - 7 ) + 13}{2 \cdot 5} : 2

u = \frac{- ( - 7 ) - 13}{2 \cdot 5} : - \frac{3}{5}

The solutions to the quadratic equation are:

u = 2, u = - \frac{3}{5}

2 a^{2} pq + 2 ab p g - 112 b^{2} pq

\frac{x ^{- 3}}{x ^{- 8}}

1 - 12 x = - 20 - 9 x

- 4 = \frac{x}{2}

What are the solutions to the equation 5u^2-7u-6=0 ?
The solutions to the equation 5u^2-7u-6=0 are u=2,u=-3/5
Find the zeros of 5u^2-7u-6=0
The zeros of 5u^2-7u-6=0 are u=2,u=-3/5