What are the solutions to the equation 2x^2+11x+9=10x+10 ?

The solutions to the equation 2x^2+11x+9=10x+10 are x= 1/2 ,x=-1

Find the zeros of 2x^2+11x+9=10x+10

The zeros of 2x^2+11x+9=10x+10 are x= 1/2 ,x=-1

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2 x^{2} + 11 x + 9 = 10 x + 10

x = \frac{1}{2}, x = - 1

Solution steps

2 x^{2} + 11 x + 9 = 10 x + 10

Move

10

to the left side

2 x^{2} + 11 x - 1 = 10 x

Move

10 x

to the left side

2 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 1) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 2}, x_{2} = \frac{- 1 - 3}{2 \cdot 2}

x = \frac{- 1 + 3}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 1 - 3}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 1

11 \geq 3 x - 7 x + 3 - 1

\frac{2 ^{3}}{2 ^{5}}

- 4 x^{2} > 16

x^{2} + 7 x + 22 = 0

10 - 4 x \leq 7

What are the solutions to the equation 2x^2+11x+9=10x+10 ?
The solutions to the equation 2x^2+11x+9=10x+10 are x= 1/2 ,x=-1
Find the zeros of 2x^2+11x+9=10x+10
The zeros of 2x^2+11x+9=10x+10 are x= 1/2 ,x=-1