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受欢迎的代数 >

solvefor x,f(a+1)=(x)^2-3(x)-4

解答

求解

x, f (a + 1) = (x)^{2} - 3 (x) - 4

解答

x = \frac{3 + 4 f + 4 a f + 25}{2}, x = \frac{3 - 4 f + 4 a f + 25}{2}

求解步骤

f (a + 1) = x^{2} - 3 (x) - 4

展开

f (a + 1) : a f + f

a f + f = x^{2} - 3 x - 4

交换两边

x^{2} - 3 x - 4 = a f + f

将

f

para o lado esquerdo

x^{2} - 3 x - 4 - f = a f

将

a f

para o lado esquerdo

x^{2} - 3 x - 4 - f - a f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 4 - f - a f )}{2 \cdot 1}

化简

(- 3)^{2} - 4 \cdot 1 \cdot (- 4 - f - a f) : 4 f + 4 a f + 25

x_{1, 2} = \frac{- ( - 3 ) \pm 4 f + 4 a f + 25}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 3 ) + 4 f + 4 a f + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 4 f + 4 a f + 25}{2 \cdot 1}

x = \frac{- ( - 3 ) + 4 f + 4 a f + 25}{2 \cdot 1} : \frac{3 + 4 f + 4 a f + 25}{2}

x = \frac{- ( - 3 ) - 4 f + 4 a f + 25}{2 \cdot 1} : \frac{3 - 4 f + 4 a f + 25}{2}

二次方程组的解是:

x = \frac{3 + 4 f + 4 a f + 25}{2}, x = \frac{3 - 4 f + 4 a f + 25}{2}

作图

流行的例子

solvefor a,4a^2-16b^2=(2a-4b)2

so l v e f or a, 4 a^{2} - 16 b^{2} = (2 a - 4 b) 2

solvefor x,fx=-14x^2+185x+360

so l v e f or x, f x = - 14 x^{2} + 185 x + 360

solvefor p,p^2+q^2=z

so l v e f or p, p^{2} + q^{2} = z

-(a/2)^2+3(-a/2)+1=0

- (\frac{a}{2})^{2} + 3 (- \frac{a}{2}) + 1 = 0

(2x-2.4)^2= 5/12

(2 x - 2.4)^{2} = \frac{5}{12}