x^2+(3-2a)x-6a=0

解答

x^{2} + (3 - 2 a) x - 6 a = 0

x = 2 a, x = - 3

求解步骤

x^{2} + (3 - 2 a) x - 6 a = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 3 - 2 a ) \pm ( 3 - 2 a ) ^{2} - 4 \cdot 1 \cdot ( - 6 a )}{2 \cdot 1}

化简

(3 - 2 a)^{2} - 4 \cdot 1 \cdot (- 6 a) : 2 a + 3

x_{1, 2} = \frac{- ( 3 - 2 a ) \pm ( 2 a + 3 )}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( 3 - 2 a ) + 2 a + 3}{2 \cdot 1}, x_{2} = \frac{- ( 3 - 2 a ) - ( 2 a + 3 )}{2 \cdot 1}

x = \frac{- ( 3 - 2 a ) + 2 a + 3}{2 \cdot 1} : 2 a

x = \frac{- ( 3 - 2 a ) - ( 2 a + 3 )}{2 \cdot 1} : - 3

二次方程组的解是:

x = 2 a, x = - 3

9.8 = 4.9 t^{2}

(n) = \frac{n ^{2}}{2} - 3 \frac{n}{2}

x^{2} - x + 1 = 0, x = 1 x = - 1

so l v e f or x, 2 x \cdot (6 x - 2 y^{2}) + 3 y^{2} (x - 4) = 8

x^{2} + (m - 1) x + 2 m - 6 = 0