What are the solutions to the equation 4w^2+24w=0 ?

The solutions to the equation 4w^2+24w=0 are w=0,w=-6

Find the zeros of 4w^2+24w=0

The zeros of 4w^2+24w=0 are w=0,w=-6

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4 w^{2} + 24 w = 0

w = 0, w = - 6

Solution steps

4 w^{2} + 24 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 \cdot 0 = 24

w_{1, 2} = \frac{- 24 \pm 24}{2 \cdot 4}

Separate the solutions

w_{1} = \frac{- 24 + 24}{2 \cdot 4}, w_{2} = \frac{- 24 - 24}{2 \cdot 4}

w = \frac{- 24 + 24}{2 \cdot 4} : 0

w = \frac{- 24 - 24}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

w = 0, w = - 6

(x + 6) (1 - x) (x - 4) \leq 0

(\frac{1}{2})^{x - 1}

(5^{- 4})^{0}

∣ 6 x - 5 ∣ > x^{2} + 3 x - 5

\frac{b + 4}{7} = - 3

What are the solutions to the equation 4w^2+24w=0 ?
The solutions to the equation 4w^2+24w=0 are w=0,w=-6
Find the zeros of 4w^2+24w=0
The zeros of 4w^2+24w=0 are w=0,w=-6