What are the solutions to the equation x^2+3x+2x+6=0 ?

The solutions to the equation x^2+3x+2x+6=0 are x=-2,x=-3

Find the zeros of x^2+3x+2x+6=0

The zeros of x^2+3x+2x+6=0 are x=-2,x=-3

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x^{2} + 3 x + 2 x + 6 = 0

x = - 2, x = - 3

Solution steps

x^{2} + 3 x + 2 x + 6 = 0

Refine

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

4 m^{2} + 9 m + 5

- 4.9 t^{2} = 9.8 t^{2} + 19.6 t - 9.8

0.0001 (300)^{3} + 0.005 (300)^{2} + 28 (300) + 3000

x^{2} + 4 = 7 x - 3

(\frac{4}{7})^{- 1}

What are the solutions to the equation x^2+3x+2x+6=0 ?
The solutions to the equation x^2+3x+2x+6=0 are x=-2,x=-3
Find the zeros of x^2+3x+2x+6=0
The zeros of x^2+3x+2x+6=0 are x=-2,x=-3