What are the solutions to the equation 3x^2-6x=15 ?

The solutions to the equation 3x^2-6x=15 are x=1+sqrt(6),x=1-sqrt(6)

Find the zeros of 3x^2-6x=15

The zeros of 3x^2-6x=15 are x=1+sqrt(6),x=1-sqrt(6)

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3 x^{2} - 6 x = 15

x = 1 + 6, x = 1 - 6

Solution steps

3 x^{2} - 6 x = 15

Move

15

to the left side

3 x^{2} - 6 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 15) = 66

x_{1, 2} = \frac{- ( - 6 ) \pm 6 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 6}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 6}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 6}{2 \cdot 3} : 1 + 6

x = \frac{- ( - 6 ) - 6 6}{2 \cdot 3} : 1 - 6

The solutions to the quadratic equation are:

x = 1 + 6, x = 1 - 6

3 - 2 i

2 \cdot 2 \cdot 2

10 x^{2} - 9 x + 2 = 0

(- 1)^{\frac{2}{3}}

2 x + 12 \geq 6

What are the solutions to the equation 3x^2-6x=15 ?
The solutions to the equation 3x^2-6x=15 are x=1+sqrt(6),x=1-sqrt(6)
Find the zeros of 3x^2-6x=15
The zeros of 3x^2-6x=15 are x=1+sqrt(6),x=1-sqrt(6)