What are the solutions to the equation x^2-14x+40=0 ?

The solutions to the equation x^2-14x+40=0 are x=10,x=4

Find the zeros of x^2-14x+40=0

The zeros of x^2-14x+40=0 are x=10,x=4

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x^{2} - 14 x + 40 = 0

x = 10, x = 4

Solution steps

x^{2} - 14 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 40 = 6

x_{1, 2} = \frac{- ( - 14 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 6}{2 \cdot 1}

x = \frac{- ( - 14 ) + 6}{2 \cdot 1} : 10

x = \frac{- ( - 14 ) - 6}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 10, x = 4

9 x^{2} - 9 = 0

(4 x)^{\frac{1}{2}}

6 m^{2} n p^{2} - 15 m n^{2} p^{2} + 9 mn p^{3}

\frac{( - 3 x ^{2} y ) ^{- 2} y ^{2}}{- x ^{2} y ^{- 5}}

26 a + 13

What are the solutions to the equation x^2-14x+40=0 ?
The solutions to the equation x^2-14x+40=0 are x=10,x=4
Find the zeros of x^2-14x+40=0
The zeros of x^2-14x+40=0 are x=10,x=4