What are the solutions to the equation y^2=-17y ?

The solutions to the equation y^2=-17y are y=0,y=-17

Find the zeros of y^2=-17y

The zeros of y^2=-17y are y=0,y=-17

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y^{2} = - 17 y

y = 0, y = - 17

Solution steps

y^{2} = - 17 y

Move

17 y

to the left side

y^{2} + 17 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 0 = 17

y_{1, 2} = \frac{- 17 \pm 17}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 17 + 17}{2 \cdot 1}, y_{2} = \frac{- 17 - 17}{2 \cdot 1}

y = \frac{- 17 + 17}{2 \cdot 1} : 0

y = \frac{- 17 - 17}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

y = 0, y = - 17

\frac{2}{5 - 3 i}

\frac{16 3}{2}

4 x + 11 = 15

4 + 3 x y - 6 y - 2 x

- 6 - 12 \div (- 6)

What are the solutions to the equation y^2=-17y ?
The solutions to the equation y^2=-17y are y=0,y=-17
Find the zeros of y^2=-17y
The zeros of y^2=-17y are y=0,y=-17