What are the solutions to the equation r^2-6r+34=0 ?

The solutions to the equation r^2-6r+34=0 are r=3+5i,r=3-5i

Find the zeros of r^2-6r+34=0

The zeros of r^2-6r+34=0 are r=3+5i,r=3-5i

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r^{2} - 6 r + 34 = 0

r = 3 + 5 i, r = 3 - 5 i

Solution steps

r^{2} - 6 r + 34 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 34 : 10 i

r_{1, 2} = \frac{- ( - 6 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 10 i}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 10 i}{2 \cdot 1}

r = \frac{- ( - 6 ) + 10 i}{2 \cdot 1} : 3 + 5 i

r = \frac{- ( - 6 ) - 10 i}{2 \cdot 1} : 3 - 5 i

The solutions to the quadratic equation are:

r = 3 + 5 i, r = 3 - 5 i

(3.2)^{2} + (- 0.6)^{2}

- 6 \leq x \leq - 3

25 (x^{2} - 1) + 6 = - 10

r - 8 \leq 7

7 y = 3 y^{2} + 2

What are the solutions to the equation r^2-6r+34=0 ?
The solutions to the equation r^2-6r+34=0 are r=3+5i,r=3-5i
Find the zeros of r^2-6r+34=0
The zeros of r^2-6r+34=0 are r=3+5i,r=3-5i