What are the solutions to the equation -2x^2+4x-29=0 ?

The solutions to the equation -2x^2+4x-29=0 are x=1-i(3sqrt(6))/2 ,x=1+i(3sqrt(6))/2

Find the zeros of -2x^2+4x-29=0

The zeros of -2x^2+4x-29=0 are x=1-i(3sqrt(6))/2 ,x=1+i(3sqrt(6))/2

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- 2 x^{2} + 4 x - 29 = 0

x = 1 - i \frac{3 6}{2}, x = 1 + i \frac{3 6}{2}

Solution steps

- 2 x^{2} + 4 x - 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( - 29 )}{2 ( - 2 )}

Simplify

4^{2} - 4 (- 2) (- 29) : 66 i

x_{1, 2} = \frac{- 4 \pm 6 6 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 6 6 i}{2 ( - 2 )}, x_{2} = \frac{- 4 - 6 6 i}{2 ( - 2 )}

x = \frac{- 4 + 6 6 i}{2 ( - 2 )} : 1 - i \frac{3 6}{2}

x = \frac{- 4 - 6 6 i}{2 ( - 2 )} : 1 + i \frac{3 6}{2}

The solutions to the quadratic equation are:

x = 1 - i \frac{3 6}{2}, x = 1 + i \frac{3 6}{2}

x^{2} - 10 x y + 24 y^{2}

- 4 + 4

4 (3 x + 3) = 5 (6 + 2 x)

4 x^{2} - 4 x - 15

\frac{4}{3} - 3 x \leq - (1 + 8 x)

What are the solutions to the equation -2x^2+4x-29=0 ?
The solutions to the equation -2x^2+4x-29=0 are x=1-i(3sqrt(6))/2 ,x=1+i(3sqrt(6))/2
Find the zeros of -2x^2+4x-29=0
The zeros of -2x^2+4x-29=0 are x=1-i(3sqrt(6))/2 ,x=1+i(3sqrt(6))/2