What is 7/4-(5/3+2/3*1/5)+2 ?

The solution to 7/4-(5/3+2/3*1/5)+2 is 1 19/20

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7/4-(5/3+2/3*1/5)+2

\frac{7}{4} - (\frac{5}{3} + \frac{2}{3} \cdot \frac{1}{5}) + 2

1 \frac{19}{20}

Solution steps

\frac{7}{4} - (\frac{5}{3} + \frac{2}{3} \cdot \frac{1}{5}) + 2

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{5}{3} + \frac{2}{3} \cdot \frac{1}{5}) : \frac{9}{5}

= \frac{7}{4} - \frac{9}{5} + 2

Add and subtract (left to right)

\frac{7}{4} - \frac{9}{5} + 2 : \frac{39}{20}

= \frac{39}{20}

Convert improper fractions to mixed numbers:

\frac{39}{20} = 1 \frac{19}{20}

= 1 \frac{19}{20}

4 n^{2} + 28 n + 49

14 4^{- \frac{1}{2}}

x^{4} + x^{5} y^{4}

\frac{1}{144}

x^{3} - 14 x^{2} + 49 x