x(2x+7)>= 0

Lösung

x (2 x + 7) \geq 0

x \leq - \frac{7}{2} or x \geq 0

Intervall-Notation

(- \infty, - \frac{7}{2}] \cup [0, \infty)

Dezimale

x \leq - 3.5 or x \geq 0

Schritte zur Lösung

x (2 x + 7) \geq 0

Identifiziere die Intervalle

x \leq - \frac{7}{2} or x \geq 0

x^{2} - 9 x + 14 \geq 0

f a c t or 7 x^{2} + x - 8

4 x - 1 = x + 2

6 (x - 1)^{2} + 13 (x - 1) - 8 = 0

3 y + 10 \leq 4