What are the solutions to the equation 10y^2-y-93=0 ?

The solutions to the equation 10y^2-y-93=0 are y= 31/10 ,y=-3

Find the zeros of 10y^2-y-93=0

The zeros of 10y^2-y-93=0 are y= 31/10 ,y=-3

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10 y^{2} - y - 93 = 0

y = \frac{31}{10}, y = - 3

Solution steps

10 y^{2} - y - 93 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 10 ( - 93 )}{2 \cdot 10}

(- 1)^{2} - 4 \cdot 10 (- 93) = 61

y_{1, 2} = \frac{- ( - 1 ) \pm 61}{2 \cdot 10}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 61}{2 \cdot 10}, y_{2} = \frac{- ( - 1 ) - 61}{2 \cdot 10}

y = \frac{- ( - 1 ) + 61}{2 \cdot 10} : \frac{31}{10}

y = \frac{- ( - 1 ) - 61}{2 \cdot 10} : - 3

The solutions to the quadratic equation are:

y = \frac{31}{10}, y = - 3

a^{9} - b^{3}

5 \cdot \frac{3}{5}

\frac{4 ^{2}}{- 5}

∣ 4 x + 2 ∣ - 17 = 5

\frac{\frac{x}{y} - \frac{y}{x}}{\frac{1}{y} + \frac{1}{x}}

What are the solutions to the equation 10y^2-y-93=0 ?
The solutions to the equation 10y^2-y-93=0 are y= 31/10 ,y=-3
Find the zeros of 10y^2-y-93=0
The zeros of 10y^2-y-93=0 are y= 31/10 ,y=-3