What are the solutions to the equation 2x^2+9x-4=0 ?

The solutions to the equation 2x^2+9x-4=0 are x=(-9+sqrt(113))/4 ,x=(-9-sqrt(113))/4

Find the zeros of 2x^2+9x-4=0

The zeros of 2x^2+9x-4=0 are x=(-9+sqrt(113))/4 ,x=(-9-sqrt(113))/4

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2 x^{2} + 9 x - 4 = 0

x = \frac{- 9 + 113}{4}, x = \frac{- 9 - 113}{4}

Solution steps

2 x^{2} + 9 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 4) = 113

x_{1, 2} = \frac{- 9 \pm 113}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 113}{2 \cdot 2}, x_{2} = \frac{- 9 - 113}{2 \cdot 2}

x = \frac{- 9 + 113}{2 \cdot 2} : \frac{- 9 + 113}{4}

x = \frac{- 9 - 113}{2 \cdot 2} : \frac{- 9 - 113}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 113}{4}, x = \frac{- 9 - 113}{4}

\frac{7}{13} x - 1 > \frac{1}{2}

x^{2} (x - 8) + 15 (x - 8)

x^{2} - 8 x + 15

2.4 = - \frac{t}{4.5}

3 x^{2} - 18 x + 24

What are the solutions to the equation 2x^2+9x-4=0 ?
The solutions to the equation 2x^2+9x-4=0 are x=(-9+sqrt(113))/4 ,x=(-9-sqrt(113))/4
Find the zeros of 2x^2+9x-4=0
The zeros of 2x^2+9x-4=0 are x=(-9+sqrt(113))/4 ,x=(-9-sqrt(113))/4