What are the solutions to the equation -x^2+6x=x^2-2x ?

The solutions to the equation -x^2+6x=x^2-2x are x=0,x=4

Find the zeros of -x^2+6x=x^2-2x

The zeros of -x^2+6x=x^2-2x are x=0,x=4

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- x^{2} + 6 x = x^{2} - 2 x

x = 0, x = 4

Solution steps

- x^{2} + 6 x = x^{2} - 2 x

Move

2 x

to the left side

- x^{2} + 8 x = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 ( - 2 )}, x_{2} = \frac{- 8 - 8}{2 ( - 2 )}

x = \frac{- 8 + 8}{2 ( - 2 )} : 0

x = \frac{- 8 - 8}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = 0, x = 4

- 2 r - 14 = 14

x^{2} - 2 x = 2

\frac{3}{3 x y} + \frac{2 y}{6 x}

9 x^{2} - 3 x - 4 = 0

90 = 66 e^{- 0.0174 (90)} + 75

What are the solutions to the equation -x^2+6x=x^2-2x ?
The solutions to the equation -x^2+6x=x^2-2x are x=0,x=4
Find the zeros of -x^2+6x=x^2-2x
The zeros of -x^2+6x=x^2-2x are x=0,x=4