What are the solutions to the equation 4x^2+10=11 ?

The solutions to the equation 4x^2+10=11 are x= 1/2 ,x=-1/2

Find the zeros of 4x^2+10=11

The zeros of 4x^2+10=11 are x= 1/2 ,x=-1/2

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4 x^{2} + 10 = 11

x = \frac{1}{2}, x = - \frac{1}{2}

Solution steps

4 x^{2} + 10 = 11

Move

10

to the right side

4 x^{2} = 1

Divide both sides by

4

x^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{4}, x = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

x^{2} - 10 x + 11 = 0

2 x - 3 < 0

12 x^{4} + 10 x^{3} - 8 x^{2}

\frac{x x ^{8} y ^{- 3}}{y ^{7}}

(x + 2)^{2} - (2 y + 1)^{2}

What are the solutions to the equation 4x^2+10=11 ?
The solutions to the equation 4x^2+10=11 are x= 1/2 ,x=-1/2
Find the zeros of 4x^2+10=11
The zeros of 4x^2+10=11 are x= 1/2 ,x=-1/2