sqrt(2)x^2+2sqrt(2)x=0

解答

2 x^{2} + 22 x = 0

x = 0, x = - 2

求解步骤

2 x^{2} + 22 x = 0

使用求根公式求解

x_{1, 2} = \frac{- 2 2 \pm ( 2 2 ) ^{2} - 4 2 \cdot 0}{2 2}

(22)^{2} - 42 \cdot 0 = 22

x_{1, 2} = \frac{- 2 2 \pm 2 2}{2 2}

将解分隔开

x_{1} = \frac{- 2 2 + 2 2}{2 2}, x_{2} = \frac{- 2 2 - 2 2}{2 2}

x = \frac{- 2 2 + 2 2}{2 2} : 0

x = \frac{- 2 2 - 2 2}{2 2} : - 2

二次方程组的解是:

x = 0, x = - 2

(2 x - 1) (x - 5) = 0

- 11 = 0.039 x^{2} - 0.9675 x

q u a d r a t i c f or m u l a x^{2} + 12 x + 35 = 0

(x + 2)^{2} - 6 = x + 2

2 x^{2} + x - 12 = 0