λ^2+5λ+6=0

解

λ^{2} + 5 λ + 6 = 0

λ = - 2, λ = - 3

解答ステップ

λ^{2} + 5 λ + 6 = 0

解くとthe二次式

λ_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

λ_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

解を分離する

λ_{1} = \frac{- 5 + 1}{2 \cdot 1}, λ_{2} = \frac{- 5 - 1}{2 \cdot 1}

λ = \frac{- 5 + 1}{2 \cdot 1} : - 2

λ = \frac{- 5 - 1}{2 \cdot 1} : - 3

二次equationの解:

λ = - 2, λ = - 3