x^2-41x+400=0

解

x^{2} - 41 x + 400 = 0

x = 25, x = 16

解答ステップ

x^{2} - 41 x + 400 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 1 \cdot 400}{2 \cdot 1}

(- 41)^{2} - 4 \cdot 1 \cdot 400 = 9

x_{1, 2} = \frac{- ( - 41 ) \pm 9}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( - 41 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 41 ) - 9}{2 \cdot 1}

x = \frac{- ( - 41 ) + 9}{2 \cdot 1} : 25

x = \frac{- ( - 41 ) - 9}{2 \cdot 1} : 16

二次equationの解:

x = 25, x = 16