What are the solutions to the equation -6x^2+48x+54=0 ?

The solutions to the equation -6x^2+48x+54=0 are x=-1,x=9

Find the zeros of -6x^2+48x+54=0

The zeros of -6x^2+48x+54=0 are x=-1,x=9

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- 6 x^{2} + 48 x + 54 = 0

x = - 1, x = 9

Solution steps

- 6 x^{2} + 48 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 ( - 6 ) \cdot 54}{2 ( - 6 )}

4 8^{2} - 4 (- 6) \cdot 54 = 60

x_{1, 2} = \frac{- 48 \pm 60}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 48 + 60}{2 ( - 6 )}, x_{2} = \frac{- 48 - 60}{2 ( - 6 )}

x = \frac{- 48 + 60}{2 ( - 6 )} : - 1

x = \frac{- 48 - 60}{2 ( - 6 )} : 9

The solutions to the quadratic equation are:

x = - 1, x = 9

4 a^{2} - 81 b^{2}

\frac{1}{4} \cdot 7

6 x^{2} - 42 x + 60 = 0

\frac{1.4 \cdot 1 0 ^{- 8}}{3.5 \cdot 1 0 ^{- 13}}

16 a^{2} - 49 b^{2}

What are the solutions to the equation -6x^2+48x+54=0 ?
The solutions to the equation -6x^2+48x+54=0 are x=-1,x=9
Find the zeros of -6x^2+48x+54=0
The zeros of -6x^2+48x+54=0 are x=-1,x=9