x^2+10x-56=0

解

x^{2} + 10 x - 56 = 0

x = 4, x = - 14

解答ステップ

x^{2} + 10 x - 56 = 0

解くとthe二次式

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 56) = 18

x_{1, 2} = \frac{- 10 \pm 18}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 10 + 18}{2 \cdot 1}, x_{2} = \frac{- 10 - 18}{2 \cdot 1}

x = \frac{- 10 + 18}{2 \cdot 1} : 4

x = \frac{- 10 - 18}{2 \cdot 1} : - 14

二次equationの解:

x = 4, x = - 14