What are the solutions to the equation -4x^2+24x-152=0 ?

The solutions to the equation -4x^2+24x-152=0 are x=3-sqrt(29)i,x=3+sqrt(29)i

Find the zeros of -4x^2+24x-152=0

The zeros of -4x^2+24x-152=0 are x=3-sqrt(29)i,x=3+sqrt(29)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} + 24 x - 152 = 0

x = 3 - 29 i, x = 3 + 29 i

Solution steps

- 4 x^{2} + 24 x - 152 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 4 ) ( - 152 )}{2 ( - 4 )}

Simplify

2 4^{2} - 4 (- 4) (- 152) : 829 i

x_{1, 2} = \frac{- 24 \pm 8 29 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 24 + 8 29 i}{2 ( - 4 )}, x_{2} = \frac{- 24 - 8 29 i}{2 ( - 4 )}

x = \frac{- 24 + 8 29 i}{2 ( - 4 )} : 3 - 29 i

x = \frac{- 24 - 8 29 i}{2 ( - 4 )} : 3 + 29 i

The solutions to the quadratic equation are:

x = 3 - 29 i, x = 3 + 29 i

∣ x ∣ = 15

5 ∣ 3 + 7 m ∣ + 1 = 51

(10 n)^{\frac{3}{2}}

\frac{x}{5} > 30

\frac{2}{3} + \frac{2}{4}

What are the solutions to the equation -4x^2+24x-152=0 ?
The solutions to the equation -4x^2+24x-152=0 are x=3-sqrt(29)i,x=3+sqrt(29)i
Find the zeros of -4x^2+24x-152=0
The zeros of -4x^2+24x-152=0 are x=3-sqrt(29)i,x=3+sqrt(29)i