What are the solutions to the equation 3b^2+5b-16=-4 ?

The solutions to the equation 3b^2+5b-16=-4 are b= 4/3 ,b=-3

Find the zeros of 3b^2+5b-16=-4

The zeros of 3b^2+5b-16=-4 are b= 4/3 ,b=-3

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3 b^{2} + 5 b - 16 = - 4

b = \frac{4}{3}, b = - 3

Solution steps

3 b^{2} + 5 b - 16 = - 4

Move

4

to the left side

3 b^{2} + 5 b - 12 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 12) = 13

b_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- 5 + 13}{2 \cdot 3}, b_{2} = \frac{- 5 - 13}{2 \cdot 3}

b = \frac{- 5 + 13}{2 \cdot 3} : \frac{4}{3}

b = \frac{- 5 - 13}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

b = \frac{4}{3}, b = - 3

3 - ln (2 x) < 2

ln (\frac{1}{e ^{3}})

a - 1 < 7

∣ 7 + x ∣ + 10 = 3

2 (x + 4 x) + 3 = 11 - 2 + 4 x

What are the solutions to the equation 3b^2+5b-16=-4 ?
The solutions to the equation 3b^2+5b-16=-4 are b= 4/3 ,b=-3
Find the zeros of 3b^2+5b-16=-4
The zeros of 3b^2+5b-16=-4 are b= 4/3 ,b=-3