簡約 10^{10}(1.602*10^{-19})(1340+461.3)

解

簡約

1 0^{10} (1.602 \cdot 1 0^{- 19}) (1340 + 461.3)

1 0^{10} \cdot \frac{14428413}{5000 \cdot 1 0 ^{19}}

十進法表記

2.88568 E - 6

解答ステップ

1 0^{10} (1.602 \cdot 1 0^{- 19}) (1340 + 461.3)

簡素化

1.602 \cdot 1 0^{- 19} : \frac{801}{500 \cdot 1 0 ^{19}}

= 1 0^{10} \cdot \frac{801}{500 \cdot 1 0 ^{19}} (1340 + 461.3)

1340 + 461.3 = 1801.3

= 1 0^{10} \cdot \frac{801}{500 \cdot 1 0 ^{19}} \cdot 1801.3

1 0^{10} \cdot \frac{801}{500 \cdot 1 0 ^{19}} \cdot 1801.3 = 1 0^{10} \cdot \frac{1442841.3}{1 0 ^{19} \cdot 500}

= 1 0^{10} \cdot \frac{1442841.3}{1 0 ^{19} \cdot 500}

\frac{1442841.3}{1 0 ^{19} \cdot 500} = \frac{14428413}{5000 \cdot 1 0 ^{19}}

= 1 0^{10} \cdot \frac{14428413}{5000 \cdot 1 0 ^{19}}