What are the solutions to the equation 4x^2+8=196 ?

The solutions to the equation 4x^2+8=196 are x=sqrt(47),x=-sqrt(47)

Find the zeros of 4x^2+8=196

The zeros of 4x^2+8=196 are x=sqrt(47),x=-sqrt(47)

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4 x^{2} + 8 = 196

x = 47, x = - 47

Solution steps

4 x^{2} + 8 = 196

Move

8

to the right side

4 x^{2} = 188

Divide both sides by

4

x^{2} = 47

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 47, x = - 47

3 x^{2} = 8

\frac{- 3 + 5}{2}

∣ x - 6 ∣ = - 5

3 \leq \frac{2 x - 3}{5} < 7

5 x - 9 = 2 x + 18

What are the solutions to the equation 4x^2+8=196 ?
The solutions to the equation 4x^2+8=196 are x=sqrt(47),x=-sqrt(47)
Find the zeros of 4x^2+8=196
The zeros of 4x^2+8=196 are x=sqrt(47),x=-sqrt(47)