What is |2-x^3|<= 6 ?

The solution to |2-x^3|<= 6 is -\sqrt[3]{4}<= x<= 2

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|2-x^3|<= 6

2 - x^{3} \leq 6

Solution steps

2 - x^{3} \leq 6

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 6 \leq 2 - x^{3} \leq 6

2 - x^{3} \geq - 6 and 2 - x^{3} \leq 6

Merge Overlapping Intervals

4^{\frac{1}{3}} \cdot 2^{\frac{1}{3}}

\frac{π}{12} - π

∣ 3 x - 2 ∣ < 7

z^{2} + 5 z - 14

0.8 5^{2}