化简 2ckx((bx-bd)/a-2b+z)

解答

化简

2 c k x (\frac{b x - b d}{a} - 2 b + z)

\frac{2 c k x ( b x - b d - 2 ba + z a )}{a}

求解步骤

2 c k x (\frac{b x - b d}{a} - 2 b + z)

合并

\frac{b x - b d}{a} - 2 b + z : \frac{b x - b d - 2 ba + z a}{a}

= 2 c k x \frac{b x - b d - 2 ba + z a}{a}

使用分式法则:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 c k x ( b x - b d - 2 ba + z a )}{a}

s im pl i f y 2 (2 + 15)

e x p an d - z \frac{d}{d z} (\frac{a z ( z + a )}{( z - a ) ^{3}})

e x p an d \frac{( x - 1 )}{2 \cdot ( x - 3 ) ^{2}}

e x p an d \frac{13 ( s + 2 ) ( s + 1 )}{s ^{3} + 9 s ^{2} + 138 s + 260}

e x p an d d x (3 x - \frac{2}{x} + 1)