What is the answer to 4(x+2)(x-2)=(2x)^2+8x ?

The answer to 4(x+2)(x-2)=(2x)^2+8x is x=-2

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4(x+2)(x-2)=(2x)^2+8x

4 (x + 2) (x - 2) = (2 x)^{2} + 8 x

x = - 2

Solution steps

4 (x + 2) (x - 2) = (2 x)^{2} + 8 x

Simplify

(2 x)^{2} + 8 x : 4 x^{2} + 8 x

4 (x + 2) (x - 2) = 4 x^{2} + 8 x

Expand

(x + 2) (x - 2) : x^{2} - 4

4 (x^{2} - 4) = 4 x^{2} + 8 x

Expand

4 (x^{2} - 4) : 4 x^{2} - 16

4 x^{2} - 16 = 4 x^{2} + 8 x

Move

16

to the right side

4 x^{2} = 4 x^{2} + 8 x + 16

Subtract

4 x^{2} + 8 x

from both sides

4 x^{2} - (4 x^{2} + 8 x) = 4 x^{2} + 8 x + 16 - (4 x^{2} + 8 x)

Simplify

- 8 x = 16

Divide both sides by

- 8

x = - 2

4 x + 28

8 r^{2} + 3 r + 2 = 7 r^{2}

2 (x - 5) + 7 = x + 8

9 x^{2} - 48 x + 64

\frac{a}{- 3} - 6 = - 1

What is the answer to 4(x+2)(x-2)=(2x)^2+8x ?
The answer to 4(x+2)(x-2)=(2x)^2+8x is x=-2
Solve for x: 4(x+2)(x-2)=(2x)^2+8x
The solution is x=-2