What are the solutions to the equation -2x^2+3x=4x-15 ?

The solutions to the equation -2x^2+3x=4x-15 are x=-3,x= 5/2

Find the zeros of -2x^2+3x=4x-15

The zeros of -2x^2+3x=4x-15 are x=-3,x= 5/2

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- 2 x^{2} + 3 x = 4 x - 15

x = - 3, x = \frac{5}{2}

Solution steps

- 2 x^{2} + 3 x = 4 x - 15

Move

15

to the left side

- 2 x^{2} + 3 x + 15 = 4 x

Move

4 x

to the left side

- 2 x^{2} - x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 2 ) \cdot 15}{2 ( - 2 )}

(- 1)^{2} - 4 (- 2) \cdot 15 = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 ( - 2 )}, x_{2} = \frac{- ( - 1 ) - 11}{2 ( - 2 )}

x = \frac{- ( - 1 ) + 11}{2 ( - 2 )} : - 3

x = \frac{- ( - 1 ) - 11}{2 ( - 2 )} : \frac{5}{2}

The solutions to the quadratic equation are:

x = - 3, x = \frac{5}{2}

∣ 3 x - 10 ∣ = 15

x^{2} = 5 x + 2

3 x - 9 = 24

(3 p^{7})^{4}

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What are the solutions to the equation -2x^2+3x=4x-15 ?
The solutions to the equation -2x^2+3x=4x-15 are x=-3,x= 5/2
Find the zeros of -2x^2+3x=4x-15
The zeros of -2x^2+3x=4x-15 are x=-3,x= 5/2