erweitern (1-x)/(2-2x)((1-2x)/(2-2x))^2

Lösung

erweitern

\frac{1 - x}{2 - 2 x} (\frac{1 - 2 x}{2 - 2 x})^{2}

\frac{1 - 4 x + 4 x ^{2}}{8 - 16 x + 8 x ^{2}}

Schritte zur Lösung

\frac{1 - x}{2 - 2 x} (\frac{1 - 2 x}{2 - 2 x})^{2}

\frac{1 - x}{2 - 2 x} = \frac{1}{2}

= \frac{1}{2} (\frac{- 2 x + 1}{- 2 x + 2})^{2}

(\frac{1 - 2 x}{2 - 2 x})^{2} = \frac{1 - 4 x + 4 x ^{2}}{4 - 8 x + 4 x ^{2}}

= \frac{1}{2} \cdot \frac{4 x ^{2} - 4 x + 1}{4 x ^{2} - 8 x + 4}

Multipliziere Brüche:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot ( 1 - 4 x + 4 x ^{2} )}{2 ( 4 - 8 x + 4 x ^{2} )}

1 \cdot (1 - 4 x + 4 x^{2}) = 1 - 4 x + 4 x^{2}

= \frac{1 - 4 x + 4 x ^{2}}{2 ( 4 x ^{2} - 8 x + 4 )}

Multipliziere aus

2 (4 - 8 x + 4 x^{2}) : 8 - 16 x + 8 x^{2}

= \frac{1 - 4 x + 4 x ^{2}}{8 - 16 x + 8 x ^{2}}

e x p an d - 5 (- v + 6 w + (- \frac{1}{2}) w)

e x p an d \frac{1}{( 2 x - 3 ) ( 2 x + 3 )}

e x p an d \frac{30 ( - k e ^{- k t} t - e ^{- k t} )}{k}

e x p an d \frac{( 50 + b ) ^{2}}{4}

e x p an d f^{'} (2) (X^{2} - 1) (2 X + 2)