What are the solutions to the equation (z+3)^2=15 ?

The solutions to the equation (z+3)^2=15 are z=sqrt(15)-3,z=-sqrt(15)-3

Find the zeros of (z+3)^2=15

The zeros of (z+3)^2=15 are z=sqrt(15)-3,z=-sqrt(15)-3

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(z + 3)^{2} = 15

z = 15 - 3, z = - 15 - 3

Solution steps

(z + 3)^{2} = 15

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 3 = 15 : z = 15 - 3

Solve

z + 3 = - 15 : z = - 15 - 3

The solutions to the quadratic equation are:

z = 15 - 3, z = - 15 - 3

a^{2} = 64

6 + \frac{4}{5} b = \frac{9}{10} b

- \frac{1}{3} - (- \frac{3}{5})

- (x - 3) - 4 (x - 1) = 14

(2 k^{3} + 6 k + 1) - (2 k^{2} + 1)

What are the solutions to the equation (z+3)^2=15 ?
The solutions to the equation (z+3)^2=15 are z=sqrt(15)-3,z=-sqrt(15)-3
Find the zeros of (z+3)^2=15
The zeros of (z+3)^2=15 are z=sqrt(15)-3,z=-sqrt(15)-3