展开 (x^2(x+1)^2)/4+(x+1)

解答

展开

\frac{x ^{2} ( x + 1 ) ^{2}}{4} + (x + 1)

\frac{x ^{4}}{4} + \frac{x ^{3}}{2} + \frac{x ^{2}}{4} + x + 1

求解步骤

\frac{x ^{2} ( x + 1 ) ^{2}}{4} + (x + 1)

去除括号:

(a) = a

= \frac{x ^{2} ( x + 1 ) ^{2}}{4} + x + 1

\frac{x ^{2} ( x + 1 ) ^{2}}{4} = \frac{x ^{4} + 2 x ^{3} + x ^{2}}{4}

= \frac{x ^{4} + 2 x ^{3} + x ^{2}}{4} + x + 1

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} + 2 x ^{3} + x ^{2}}{4} = \frac{x ^{4}}{4} + \frac{2 x ^{3}}{4} + \frac{x ^{2}}{4}

= \frac{x ^{4}}{4} + \frac{2 x ^{3}}{4} + \frac{x ^{2}}{4} + x + 1

消掉

\frac{2 x ^{3}}{4} : \frac{x ^{3}}{2}

= \frac{x ^{4}}{4} + \frac{x ^{3}}{2} + \frac{x ^{2}}{4} + x + 1

e x p an d \frac{3 ( 6 + 11 M )}{44}

\frac{d ^{2}}{d x ^{2}} ((y) (8 - x))

e x p an d 0.7 m (1 - e^{- \frac{143.08}{m}})

e x p an d \frac{4 x ^{2} + 2 x - 1}{x ^{2} ( x + 1 )}

e x p an d \frac{d ^{2}}{d x ^{2}} ((x^{2} - 3) (2 x^{6} + 3)) + (\frac{2}{e ^{x}})