展开 (4s+2s^2+8)/((s^2+4)(s+1)^2)

解答

展开

\frac{4 s + 2 s ^{2} + 8}{( s ^{2} + 4 ) ( s + 1 ) ^{2}}

\frac{4 s + 2 s ^{2} + 8}{s ^{4} + 2 s ^{3} + 5 s ^{2} + 8 s + 4}

求解步骤

\frac{4 s + 2 s ^{2} + 8}{( s ^{2} + 4 ) ( s + 1 ) ^{2}}

(s + 1)^{2} = s^{2} + 2 s + 1

= \frac{4 s + 2 s ^{2} + 8}{( s ^{2} + 4 ) ( s ^{2} + 2 s + 1 )}

乘开

(s^{2} + 4) (s^{2} + 2 s + 1) : s^{4} + 2 s^{3} + 5 s^{2} + 8 s + 4

= \frac{4 s + 2 s ^{2} + 8}{s ^{4} + 2 s ^{3} + 5 s ^{2} + 8 s + 4}

e x p an d \frac{6 x ^{2} + 21 x + 11}{( x ^{2} + 3 ) ( x + 5 )}

e x p an d \frac{( - 1 + 3 x )}{( 2 - 3 x ) ^{2}}

e x p an d f (3 - x) d x^{\frac{1}{2}}

e x p an d \frac{1 - e ^{- 3 (s - 3)}}{s - 3} + \frac{e ^{- 3 s}}{s}

e x p an d \frac{( e ^{- s} + s )}{s ( s - 6 ) ( s + 1 )}