What is (sqrt(3)-1)/(sqrt(2)-1) ?

The solution to (sqrt(3)-1)/(sqrt(2)-1) is sqrt(6)+sqrt(3)-sqrt(2)-1

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simplify (sqrt(3)-1)/(sqrt(2)-1)

simplify

\frac{3 - 1}{2 - 1}

6 + 3 - 2 - 1

Solution steps

\frac{3 - 1}{2 - 1}

Multiply by the conjugate

\frac{2 + 1}{2 + 1}

= \frac{( 3 - 1 ) ( 2 + 1 )}{( 2 - 1 ) ( 2 + 1 )}

Expand

(3 - 1) (2 + 1) : 6 + 3 - 2 - 1

Expand

(2 - 1) (2 + 1) : 1

= \frac{6 + 3 - 2 - 1}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 6 + 3 - 2 - 1

- 2.88 \leq 2.4 (f - 13)

\frac{- 2 + i}{6 - 10 i}

- 7 x + 4 = x^{2}

27 = x + 11

56 (x + 10) = 25

What is (sqrt(3)-1)/(sqrt(2)-1) ?
The solution to (sqrt(3)-1)/(sqrt(2)-1) is sqrt(6)+sqrt(3)-sqrt(2)-1