What are the solutions to the equation p^2-7p=8 ?

The solutions to the equation p^2-7p=8 are p=8,p=-1

Find the zeros of p^2-7p=8

The zeros of p^2-7p=8 are p=8,p=-1

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p^{2} - 7 p = 8

p = 8, p = - 1

Solution steps

p^{2} - 7 p = 8

Move

8

to the left side

p^{2} - 7 p - 8 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

p_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, p_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

p = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

p = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

p = 8, p = - 1

15.3 > 3 (a - 1.4)

f = 3^{(- 2)}

\frac{7 - 5 x}{3} = 2 x - 8

c^{2} - c - 2

- 17 + 3 x \leq 11 x + 7

What are the solutions to the equation p^2-7p=8 ?
The solutions to the equation p^2-7p=8 are p=8,p=-1
Find the zeros of p^2-7p=8
The zeros of p^2-7p=8 are p=8,p=-1