展开 (2k-3)(3k-3)'

解答

展开

(2 k - 3) (3 k - 3)^{'}

2 k (3 k - 3)' - 3 (3 k - 3)'

求解步骤

(2 k - 3) (3 k - 3)^{'}

使用分配律:

a (b - c) = ab - a c

a = (3 k - 3)^{'}, b = 2 k, c = 3

= (3 k - 3)^{^{'}} 2 k - (3 k - 3)^{^{'}} 3

= 2 k (3 k - 3)^{^{'}} - 3 (3 k - 3)^{^{'}}

e x p an d (x - 3 + 2 i) (x - 3 - 2 i)

e x p an d \frac{2 x + 2}{( x - 1 ) ( x + 3 )}

e x p an d (2 - x)^{4}

s im pl i f y \frac{1}{( 3 - 8 i \cdot x ) ^{5}}

e x p an d v (2, - 1) y f (4, - 1)