展开 (f\circ g)(4x+4)(x^2)

解答

展开

(f \circ g) (4 x + 4) (x^{2})

4 \circ f g x^{3} + 4 \circ f g x^{2}

求解步骤

(f \circ g) (4 x + 4) (x^{2})

= (x^{2}) (\circ f g) (4 x + 4)

使用分配律:

a (b + c) = ab + a c

a = (f \circ g) (x^{2}), b = 4 x, c = 4

= (f \circ g) (x^{2}) \cdot 4 x + (f \circ g) (x^{2}) \cdot 4

= 4 x (x^{2}) (\circ f g) + 4 (x^{2}) (\circ f g)

化简

4 x (x^{2}) (\circ f g) + 4 (x^{2}) (\circ f g) : 4 \circ f g x^{3} + 4 \circ f g x^{2}

= 4 \circ f g x^{3} + 4 \circ f g x^{2}

e x p an d \frac{6}{( x - 1 ) ( x + 1 )}

s im pl i f y (x + 2 x)^{2}

e x p an d \frac{( 2 x + v ^{2} x - 1 )}{x ^{2} ( v + 1 )}

e x p an d (t^{2} + 4 t + 4) \cdot (2^{\frac{1}{2}} (t + 2))

e x p an d \frac{( k + 1 ) ( k + 2 ) ( k + 3 )}{6}