vereinfachen ((-2a^3b^2c^0)/(3a^2b^3c^7))^{-2}

Lösung

vereinfachen

(\frac{- 2 a ^{3} b ^{2} c ^{0}}{3 a ^{2} b ^{3} c ^{7}})^{- 2}

\frac{9 b ^{2} c ^{14}}{4 a ^{2}}

Schritte zur Lösung

(\frac{- 2 a ^{3} b ^{2} c ^{0}}{3 a ^{2} b ^{3} c ^{7}})^{- 2}

Wende Exponentenregel an:

a^{- b} = \frac{1}{a ^{b}}

(\frac{- 2 a ^{3} b ^{2} c ^{0}}{3 a ^{2} b ^{3} c ^{7}})^{- 2} = \frac{1}{( \frac{- 2 a ^{3} b ^{2} c ^{0}}{3 a ^{2} b ^{3} c ^{7}} ) ^{2}}

= \frac{1}{( \frac{- 2 a ^{3} b ^{2} c ^{0}}{3 a ^{2} b ^{3} c ^{7}} ) ^{2}}

Vereinfache

(\frac{- 2 a ^{3} b ^{2} c ^{0}}{3 a ^{2} b ^{3} c ^{7}})^{2} : \frac{4 a ^{2}}{9 b ^{2} c ^{14}}

= \frac{1}{\frac{4 a ^{2}}{9 b ^{2} c ^{14}}}

Wende Bruchregel an:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{9 b ^{2} c ^{14}}{4 a ^{2}}

5 x^{2} + 6 x - 7 = 0

s im pl i f y \frac{1}{2} 12 - \frac{1}{3} 18 + \frac{3}{4} 48 + \frac{1}{6} 72

f a c t or 2 a^{2} - 8 a

- x^{2} - 7 x - 12 \leq - 2

f a c t or 6^{n} + 2^{n}