What are the solutions to the equation 12x^2-4x=20+10x ?

The solutions to the equation 12x^2-4x=20+10x are x=2,x=-5/6

Find the zeros of 12x^2-4x=20+10x

The zeros of 12x^2-4x=20+10x are x=2,x=-5/6

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12 x^{2} - 4 x = 20 + 10 x

x = 2, x = - \frac{5}{6}

Decimal Notation

x = 2, x = - 0.83333 \dots

Solution steps

12 x^{2} - 4 x = 20 + 10 x

Move

10 x

to the left side

12 x^{2} - 14 x = 20

Move

20

to the left side

12 x^{2} - 14 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 12 ( - 20 )}{2 \cdot 12}

(- 14)^{2} - 4 \cdot 12 (- 20) = 34

x_{1, 2} = \frac{- ( - 14 ) \pm 34}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 34}{2 \cdot 12}, x_{2} = \frac{- ( - 14 ) - 34}{2 \cdot 12}

x = \frac{- ( - 14 ) + 34}{2 \cdot 12} : 2

x = \frac{- ( - 14 ) - 34}{2 \cdot 12} : - \frac{5}{6}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{6}

(- x - 4) \cdot 2 = 3 \cdot (- 3 x + 1) + 12

2^{n} \cdot 3^{n}

\frac{1}{1 + e ^{- 3}}

2 x^{4} - 6 x^{2} + 4 x

What are the solutions to the equation 12x^2-4x=20+10x ?
The solutions to the equation 12x^2-4x=20+10x are x=2,x=-5/6
Find the zeros of 12x^2-4x=20+10x
The zeros of 12x^2-4x=20+10x are x=2,x=-5/6