What are the solutions to the equation 2(x+7)^2=36 ?

The solutions to the equation 2(x+7)^2=36 are x=3sqrt(2)-7,x=-3sqrt(2)-7

Find the zeros of 2(x+7)^2=36

The zeros of 2(x+7)^2=36 are x=3sqrt(2)-7,x=-3sqrt(2)-7

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2 (x + 7)^{2} = 36

x = 32 - 7, x = - 32 - 7

Decimal Notation

x = - 2.75735 \dots, x = - 11.24264 \dots

Solution steps

2 (x + 7)^{2} = 36

Divide both sides by

2

(x + 7)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 18 : x = 32 - 7

Solve

x + 7 = - 18 : x = - 32 - 7

The solutions to the quadratic equation are:

x = 32 - 7, x = - 32 - 7

e^{- i (\frac{π}{2})}

\frac{4 !}{3 ! ( 4 - 3 ) !}

\frac{0}{1} = \frac{4}{1}

(x - 4)^{2} - \frac{1}{2}

What are the solutions to the equation 2(x+7)^2=36 ?
The solutions to the equation 2(x+7)^2=36 are x=3sqrt(2)-7,x=-3sqrt(2)-7
Find the zeros of 2(x+7)^2=36
The zeros of 2(x+7)^2=36 are x=3sqrt(2)-7,x=-3sqrt(2)-7