What is -(2x+3)/((x-1)^2(x+4)^2)<0 ?

The solution to -(2x+3)/((x-1)^2(x+4)^2) 1

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-(2x+3)/((x-1)^2(x+4)^2)<0

- \frac{2 x + 3}{( x - 1 ) ^{2} ( x + 4 ) ^{2}} < 0

- \frac{3}{2} < x < 1 or x > 1

Interval Notation

(- \frac{3}{2}, 1) \cup (1, \infty)

Decimal Notation

- 1.5 < x < 1 or x > 1

Solution steps

- \frac{2 x + 3}{( x - 1 ) ^{2} ( x + 4 ) ^{2}} < 0

Rewrite in standard form

\frac{2 x + 3}{( x - 1 ) ^{2} ( x + 4 ) ^{2}} > 0

Identify the intervals

- \frac{3}{2} < x < 1 or x > 1

0 = (x + 4)^{2} - 2

19 \leq 5 x - 1 \leq 39

∣ x + 3 ∣ > 8

7 x^{2} - 20 x + 4 = 8 x - 10

m^{2} - 3 m - 10

What is -(2x+3)/((x-1)^2(x+4)^2)<0 ?
The solution to -(2x+3)/((x-1)^2(x+4)^2)<0 is -3/2 <x<1\lor x>1