What are the solutions to the equation y^2+11y+14=0 ?

The solutions to the equation y^2+11y+14=0 are y=(-11+sqrt(65))/2 ,y=(-11-sqrt(65))/2

Find the zeros of y^2+11y+14=0

The zeros of y^2+11y+14=0 are y=(-11+sqrt(65))/2 ,y=(-11-sqrt(65))/2

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y^{2} + 11 y + 14 = 0

y = \frac{- 11 + 65}{2}, y = \frac{- 11 - 65}{2}

Decimal Notation

y = - 1.46887 \dots, y = - 9.53112 \dots

Solution steps

y^{2} + 11 y + 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 14 = 65

y_{1, 2} = \frac{- 11 \pm 65}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 11 + 65}{2 \cdot 1}, y_{2} = \frac{- 11 - 65}{2 \cdot 1}

y = \frac{- 11 + 65}{2 \cdot 1} : \frac{- 11 + 65}{2}

y = \frac{- 11 - 65}{2 \cdot 1} : \frac{- 11 - 65}{2}

The solutions to the quadratic equation are:

y = \frac{- 11 + 65}{2}, y = \frac{- 11 - 65}{2}

e^{x} - 12 e^{- x} - 1 = 0

(5 x + 9) = (7 x - 9)

3 a^{- 1}

∣ 2 x + 6 ∣ - 4 = 20

\frac{( 4 \cdot 1 0 ^{- 38} )}{27}

What are the solutions to the equation y^2+11y+14=0 ?
The solutions to the equation y^2+11y+14=0 are y=(-11+sqrt(65))/2 ,y=(-11-sqrt(65))/2
Find the zeros of y^2+11y+14=0
The zeros of y^2+11y+14=0 are y=(-11+sqrt(65))/2 ,y=(-11-sqrt(65))/2