What are the solutions to the equation 5+x^2+x=3+5x^2 ?

The solutions to the equation 5+x^2+x=3+5x^2 are x=-(-1+sqrt(33))/8 ,x=(1+sqrt(33))/8

Find the zeros of 5+x^2+x=3+5x^2

The zeros of 5+x^2+x=3+5x^2 are x=-(-1+sqrt(33))/8 ,x=(1+sqrt(33))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 + x^{2} + x = 3 + 5 x^{2}

x = - \frac{- 1 + 33}{8}, x = \frac{1 + 33}{8}

Decimal Notation

x = - 0.59307 \dots, x = 0.84307 \dots

Solution steps

5 + x^{2} + x = 3 + 5 x^{2}

Move

5 x^{2}

to the left side

- 4 x^{2} + x + 5 = 3

Move

3

to the left side

- 4 x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 4 ) \cdot 2}{2 ( - 4 )}

1^{2} - 4 (- 4) \cdot 2 = 33

x_{1, 2} = \frac{- 1 \pm 33}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 1 + 33}{2 ( - 4 )}, x_{2} = \frac{- 1 - 33}{2 ( - 4 )}

x = \frac{- 1 + 33}{2 ( - 4 )} : - \frac{- 1 + 33}{8}

x = \frac{- 1 - 33}{2 ( - 4 )} : \frac{1 + 33}{8}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 33}{8}, x = \frac{1 + 33}{8}

49 x^{2} - 121 y^{2}

4 a^{2} - 6 a

3 x^{2} - 6 x + 12

2 x^{2} + 9 = - 7 x + 4

3 x + 8 = x - 2

What are the solutions to the equation 5+x^2+x=3+5x^2 ?
The solutions to the equation 5+x^2+x=3+5x^2 are x=-(-1+sqrt(33))/8 ,x=(1+sqrt(33))/8
Find the zeros of 5+x^2+x=3+5x^2
The zeros of 5+x^2+x=3+5x^2 are x=-(-1+sqrt(33))/8 ,x=(1+sqrt(33))/8