What are the solutions to the equation -4x^2+9x-2=0 ?

The solutions to the equation -4x^2+9x-2=0 are x= 1/4 ,x=2

Find the zeros of -4x^2+9x-2=0

The zeros of -4x^2+9x-2=0 are x= 1/4 ,x=2

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- 4 x^{2} + 9 x - 2 = 0

x = \frac{1}{4}, x = 2

Decimal Notation

x = 0.25, x = 2

Solution steps

- 4 x^{2} + 9 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 4 ) ( - 2 )}{2 ( - 4 )}

9^{2} - 4 (- 4) (- 2) = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 ( - 4 )}, x_{2} = \frac{- 9 - 7}{2 ( - 4 )}

x = \frac{- 9 + 7}{2 ( - 4 )} : \frac{1}{4}

x = \frac{- 9 - 7}{2 ( - 4 )} : 2

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 2

5 k^{2} + 25 k + 20

- 25 x + 12 + 12 x^{2}

x^{15}

(3 + 4 i)^{2}

x^{2} + 13 x + 36 = 0

What are the solutions to the equation -4x^2+9x-2=0 ?
The solutions to the equation -4x^2+9x-2=0 are x= 1/4 ,x=2
Find the zeros of -4x^2+9x-2=0
The zeros of -4x^2+9x-2=0 are x= 1/4 ,x=2