What are the solutions to the equation x^2-8x+16=5 ?

The solutions to the equation x^2-8x+16=5 are x=4+sqrt(5),x=4-sqrt(5)

Find the zeros of x^2-8x+16=5

The zeros of x^2-8x+16=5 are x=4+sqrt(5),x=4-sqrt(5)

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x^{2} - 8 x + 16 = 5

x = 4 + 5, x = 4 - 5

Decimal Notation

x = 6.23606 \dots, x = 1.76393 \dots

Solution steps

x^{2} - 8 x + 16 = 5

Move

5

to the left side

x^{2} - 8 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 11 = 25

x_{1, 2} = \frac{- ( - 8 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 5}{2 \cdot 1} : 4 + 5

x = \frac{- ( - 8 ) - 2 5}{2 \cdot 1} : 4 - 5

The solutions to the quadratic equation are:

x = 4 + 5, x = 4 - 5

38 = 8 x - x + 10

x^{2} + 6 x = - 8

16 \cdot \frac{5}{2}

5 x^{2} - 15 x

x \leq \frac{- x + 1}{2 x - 1}

What are the solutions to the equation x^2-8x+16=5 ?
The solutions to the equation x^2-8x+16=5 are x=4+sqrt(5),x=4-sqrt(5)
Find the zeros of x^2-8x+16=5
The zeros of x^2-8x+16=5 are x=4+sqrt(5),x=4-sqrt(5)